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Calculating Bullet Trajectory

Bullet Trajectory Equation:

\[ y = x \cdot \tan(\theta) - \frac{g \cdot x^2}{2 \cdot v^2 \cdot \cos^2(\theta)} \]

m
rad
m/s
m/s²

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1. What is the Bullet Trajectory Equation?

The bullet trajectory equation calculates the height (y) of a projectile at a given range (x) based on initial velocity, launch angle, and gravitational acceleration. It's derived from the equations of motion under constant gravity.

2. How Does the Calculator Work?

The calculator uses the trajectory equation:

\[ y = x \cdot \tan(\theta) - \frac{g \cdot x^2}{2 \cdot v^2 \cdot \cos^2(\theta)} \]

Where:

Explanation: The equation accounts for both the vertical component of initial velocity and the effect of gravity on the projectile's path.

3. Importance of Trajectory Calculation

Details: Accurate trajectory calculation is crucial for ballistics, military applications, sports science, and understanding projectile motion in physics.

4. Using the Calculator

Tips: Enter range in meters, angle in radians, velocity in m/s, and gravitational acceleration (default is 9.81 m/s²). All values must be positive.

5. Frequently Asked Questions (FAQ)

Q1: Why use radians instead of degrees for angle?
A: The trigonometric functions in the equation require angle input in radians for accurate mathematical computation.

Q2: What is the maximum range for a given velocity?
A: Maximum range occurs at a launch angle of 45 degrees (π/4 radians) when air resistance is neglected.

Q3: Does this equation account for air resistance?
A: No, this is the ideal trajectory equation that assumes no air resistance or other external forces besides gravity.

Q4: Can this be used for any projectile?
A: This equation applies to any projectile under constant gravitational acceleration when air resistance is negligible.

Q5: How accurate is this calculation for real-world applications?
A: While providing a good approximation, real-world ballistics require additional factors like air density, drag, and wind conditions for precise calculations.

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